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Tennis tournament
1998 tennis event results
Mark Philippoussis was the defending champion, but lost in the second round to Tommy Haas.
Andre Agassi won the title, defeating Jason Stoltenberg 6–4, 7–6(7–3) in the final.[1][2]
Top half[edit]
Bottom half[edit]
Qualifying[edit]
Qualifying seeds[edit]
Qualifiers[edit]
Lucky loser[edit]
Scott Draper
Special exempt[edit]
Sébastien Lareau (reached the semifinals at Philadelphia)
Qualifying draw[edit]
First qualifier[edit]
Second qualifier[edit]
Third qualifier[edit]
Fourth qualifier[edit]
References[edit]
External links[edit]
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Grand Slam events | |
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Mercedes Super 9 | |
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ATP Championship Series |
- Antwerp (S, D)
- Memphis (S, D)
- Philadelphia (S, D)
- London (S, D)
- Barcelona (S, D)
- Tokyo (S, D)
- Stuttgart (S, D)
- Washington (S, D)
- Indianapolis (S, D)
- New Haven (S, D)
- Singapore (S, D)
- Vienna (S, D)
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ATP World Series |
- Adelaide (S, D)
- Doha (S, D)
- Sydney (S, D)
- Auckland (S, D)
- Marseille (S, D)
- Split (S, D)
- Dubai (S, D)
- St. Petersburg (S, D)
- San Jose (S, D)
- Rotterdam (S, D)
- Scottsdale (S, D)
- Copenhagen (S, D)
- Casablanca (S, D)
- Hong Kong (S, D)
- Estoril (S, D)
- Chennai (S, D)
- Orlando (S, D)
- Prague (S, D)
- Atlanta (S, D)
- Munich (S, D)
- Coral Springs (S, D)
- St. Pölten (S, D)
- Halle (S, D)
- London/Queen's Club (S, D)
- Bologna (S, D)
- 's-Hertogenbosch (S, D)
- Nottingham (S, D)
- Gstaad (S, D)
- Newport (S, D)
- Båstad (S, D)
- Los Angeles (S, D)
- Umag (S, D)
- Kitzbühel (S, D)
- Amsterdam (S, D)
- San Marino (S, D)
- Long Island (S, D)
- Boston (S, D)
- Bournemouth (S, D)
- Tashkent (S, D)
- Bucharest (S, D)
- Toulouse (S, D)
- Majorca (S, D)
- Basel (S, D)
- Palermo (S, D)
- Shanghai (S, D)
- Ostrava (S, D)
- Lyon (S, D)
- Mexico City (S, D)
- Bogotá (S, D)
- Santiago (S, D)
- Moscow (S, D)
- Stockholm (S, D)
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Team events | |
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